Wednesday, February 1, 2017

GST 2.8 Keyboard Handler Question

GWT 2.8

I have the following code. It is used in a application where the input device is a usb keypad with numbers and # key.

I am trying  to use the # key as deliminator to obtains the numerics from the text box.

Everything works  except the # (Delimiter) key gets placed in the textbox after processing and I do not know how to remove it to prepare for next input.  It needs to be removed because there is no backspace key.

Code snippet follows:

        gameInput.addKeyPressHandler(new KeyPressHandler() {

            @Override
            public void onKeyPress(KeyPressEvent event) {
                int keycode = event.getCharCode();
                if (keycode == '#') {
                    String gamecode = gameInput.getText();
                   
                    gameInput.clear();
                    gameInput.setText("");

.....

Any help would be appreciated.

Best



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