I found the answers, very simple.
1st, when opening a new link we can add a param like whichLink. Ex my.com#link1;whichLink=link1
Then in HeaderPresenter, when calling GuideDialog, we do this
GuideDialogBox gDialogBox=new GuideDialogBox(placeManager.getCurrentPlaceRequest().getParameter("whichLink", "home"));
On Friday, October 25, 2013 11:15:39 PM UTC+11, Tom wrote:
Here is my problem. I have many links in my header presenter.
Link1 - Link2 - Link3 - GuideDialogLinkWhen user clicks on Link1 or Link2 or Link3, it will open a new browser.
However, when user clicks on GuideDialogLink, then it will popup a DialogBox right on top of the current link.
The GuideDialog is designed in a way that it show different Gui depending on which link user is staying. Its code is like this:
class GuideDialog extends DialogBox{ public GuideDialog(int whichLink){ if(whichLink==0){ //show Gui 1 } else if(whichLink==2){ //show Gui 2 } else if(whichLink==3){ //show Gui 3 } } }
Ex, when user is staying in Link3 & if they click GuideDialogLink, it will show a DialogBox that has Gui3 which is different from Gui1 or Gui2 if user is staying on Link1 or Link2.
So, my question is:
Is there any way to retrieve the Current Presenter?
If we know which Presenter is current one, then we can call GuideDialog accordingly ex:
GuideDialog myGD=new GuideDialog(0);
-Other solution is to store a
public static int currentLink
inUtility
class. And when user clicks link1 or link2 or link3 we can use EventBus to setpublic static currentLink
to set accordingly & eventuallyGuideDialog myGD=new GuideDialog(Utility.
.currentLink); But i don't think this solution is elegant since Google must have some function to let us know which current page we are in.
So how can i solve my problem elegantly?
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