Re: How to unescape a JSONString?

I ran into this.  GWT is too smart sometimes.  :)

For my example, I was querying an API for WebRTC ICE servers, which returned a string which was a JSON array.

When I had:

private static native JavaScriptObject createPeerConnection(String iceServersJson) /*-{
  var peerConnectionConfig = {
    iceServers: iceServersJson
  };
  return new RTCPeerConnection(peerConnectionConfig);
}-*/;

GWT excaped the quotes, so iceServers switched from an array, to just a string, exactly like I asked it to.

So, really, I needed what Thomas suggested:

JavaScriptObject iceServersObj = ((JSONArray)JSONParser.parseStrict(iceServersJson)).getJavaScriptObject();

private static native JavaScriptObject createPeerConnection(JavaScriptObject iceServersJson) /*-{
  var peerConnectionConfig = {
    iceServers: iceServersJson
  };
  return new RTCPeerConnection(peerConnectionConfig);
}-*/;

Now I'm telling GWT it's a JSO, and GWT knows not to escape it.

On Monday 9 November 2009 at 10:25:24 pm UTC+11 Thomas Broyer wrote:

On Nov 9, 11:47 am, peterk <peter.ke...@gmail.com> wrote:
> I'm having some trouble dealing with escaping and unescaping of Java
> strings for encoding in JSON.
>
> I use JSONString to encode a Java string and that seems to work ok.
> For example, newlines turn into \n, tabs turn into \t and so on.
>
> However, given this escaped sequence back, how to I turn this back
> into an unescaped javastring wheren \n is turned into a newline and so
> on?
>
> If I use stringvalue() on the JSONString it just gives back the same
> json encoded string with the \n and \t encoding etc.
>
> Anyone have any ideas? :)

JSONParser.parse? ;-)

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