Re: uncaught java.lang.indexoutofboundsexception

On Friday, October 9, 2015 at 12:32:59 PM UTC+2, NewbieGwtUser wrote:

I already expected my error and it worked fine by removing the = operator.

but unfortunately when I wanted to add the real code expected to be run within the for loop, I have had the same exception, and I also had only 1 displayed item in 2 (so that if I have 10 items, it display only 5 by skeeping every time 1 item), here is the code

              

Let's say you have 3 items.

 

              for(int i=0; i<nbMenuItems; i++){

MaterialToast.alert("ok"+ subMenuItemsContainer.getWidget(i));

MaterialRow row = new MaterialRow();

MaterialColumn col1=new MaterialColumn( 12, 6, 3);

col1.add(subMenuItemsContainer.getWidget(i));

You've just moved the first widget from subMenuItemsContainer to col1, so subMenuItemsContainer now only has 2 items.

The one at index 0 is now the one that previously was at index 1, and the one at index 1 is the one that was at index 2.

row.add(col1);

mosaiqueContainer.add(row);

}

}

I really don't understand what is the wrong with my code ???

On the second iteration of the loop, i will be 1, so subMenuItemsContainer will return the widget that initially was at index 2 (you just skipped the one that was at index 1, which has moved to index 0).

And during that iteration, you removed that item too, so subMenuItemsContainer now only contains 1 item (the one that initially was at index 1).

On the third iteration, i is 2, but SubMenuItemsContainer only has 1 item ⇒ exception.

Solution ⇒ replace your "for (int i = 0; i < nbMenuItems; i++)" with "while (subMenuItemsContainer.getWidgetCount() > 0)", and always use getWidget(0).

…except I suspect you'd actually rather not to move the widgets around, but rather somehow copy them or whatever.

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